(4x-8)/(x-3)+(3/x)=(-3)/(x^2-3x)

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Solution for (4x-8)/(x-3)+(3/x)=(-3)/(x^2-3x) equation: 



(4x-8)/(x-3)+(3/x)=(-3)/(x^2-3x)

We move all terms to the left:

(4x-8)/(x-3)+(3/x)-((-3)/(x^2-3x))=0



Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x^2-3x))!=0

x∈R



We add all the numbers together, and all the variables

(4x-8)/(x-3)+(+3/x)-((-3)/(x^2-3x))=0

We get rid of parentheses

(4x-8)/(x-3)+3/x-((-3)/(x^2-3x))=0

We calculate fractions


((4x-8)*x*(x^2-3x)))/((x-3)*x*(x^2-3x)))+(3*(x-3)*(x^2-3x)))/((x-3)*x*(x^2-3x)))+(-((-3)*(x-3)*x)/((x-3)*x*(x^2-3x)))=0

We can not solve this equation

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